CBSE Class 10 Mathematics Circles Notes
About This Chapter
Circles is Chapter 10 of the CBSE Class 10 Mathematics syllabus. This chapter moves beyond the basic definition of a circle to explore the special relationships that arise when a line meets a circle. Students study tangents and secants, learn the properties that govern them, and apply these properties to solve geometric problems involving lengths, angles, and proofs. Circles are encountered everywhere in the real world: in the design of wheels, gears, clock faces, roundabouts, and satellite dishes. The concept of a tangent underpins engineering applications such as designing smooth curves on roads and railway tracks, while the properties of chords and arcs are central to architecture and construction. In the CBSE Board Examination, this chapter typically carries 6 to 8 marks out of 80. Questions appear across short answer (2-3 mark) and long answer (4-5 mark) formats. Theorem-based proofs, tangent-length problems, and angle calculations are the most frequently tested question types. These notes provide complete coverage of every concept, theorem, formula, and example type required for board exam preparation. A downloadable PDF version is attached below. What You Will Learn:• Definitions and properties of tangents, secants, and chords of a circle • The two fundamental NCERT theorems on tangents and their complete proofs • How to calculate tangent length, angles between tangents, and related segment lengths • Real-world applications including excircles, incircles, and tangent constructions • Common mistakes, exam tips, and a full set of practice questions by mark category The complete PDF of these notes is attached below for download. |
1. Introduction and Definition
A circle is the locus of all points in a plane that are equidistant from a fixed point called the centre. The fixed distance from the centre to any point on the circle is called the radius. This chapter focuses not on the circle itself but on lines that interact with it in specific ways.
1.1 Basic Circle Terminology
Term | Definition |
Centre | The fixed point equidistant from all points on the circle |
Radius (r) | Distance from the centre to any point on the circle |
Diameter (d) | Longest chord passing through the centre; d = 2r |
Chord | A line segment with both endpoints on the circle |
Arc | A part of the circumference of the circle |
Secant | A line that intersects the circle at exactly two distinct points |
Tangent | A line that touches the circle at exactly one point (the point of tangency) |
Point of Tangency | The unique point where the tangent touches the circle |
1.2 Number of Tangents from a Point
Position of Point | Number of Tangents Possible | Description |
Inside the circle | 0 | Any line through this point cuts the circle at two points |
On the circle | 1 | Exactly one tangent can be drawn at that point |
Outside the circle | 2 | Two tangents of equal length can be drawn |
2. Key Concepts and Components
2.1 Tangent to a Circle
A tangent to a circle is a line that touches the circle at exactly one point. Unlike a secant, a tangent does not cross the circle; it merely grazes its boundary. The point at which the tangent meets the circle is called the point of contact or point of tangency.
2.2 Secant to a Circle
A secant is a line that intersects the circle at two distinct points. As the secant is moved closer and closer to become tangent to the circle, the two points of intersection converge into a single point of tangency. This is the limiting case of a secant.
2.3 Relationship Between Tangent and Radius
The most fundamental property of a tangent is the angle it makes with the radius at the point of tangency. This relationship is the foundation for virtually all circle theorems in this chapter.
Tangent-Radius Relationship |
The tangent at any point of a circle is perpendicular to the radius through the point of contact. |
2.4 Tangent from an External Point
When two tangents are drawn from an external point to a circle, they have equal length. This is a direct consequence of the congruence of the two right triangles formed by the tangents, the radii, and the line joining the external point to the centre.
Equal Tangent Lengths |
If PA and PB are tangents from external point P to a circle with centre O, then PA = PB |
3. Core Theorems and Derivations
3.1 Theorem 1: Tangent Perpendicular to Radius
Statement: The tangent at any point of a circle is perpendicular to the radius through the point of contact.
Given: A circle with centre O, tangent XY at point P on the circle.
To Prove: OP is perpendicular to XY.
Proof: Let Q be any other point on the tangent line XY. Since XY is a tangent, Q lies outside the circle. Therefore OQ > OP (as OP = radius, and OQ is greater than the shortest distance from O to the line, which is OP since OP is perpendicular). Since this is true for every point Q on XY other than P, OP is the shortest distance from O to the line XY. Therefore OP is perpendicular to XY.
Result |
OP perpendicular to XY, i.e., angle OPX = angle OPY = 90 degrees |
3.2 Theorem 2: Equal Tangents from External Point
Statement: The lengths of two tangents drawn from an external point to a circle are equal.
Given: Circle with centre O. External point P. PA and PB are tangents touching at A and B.
To Prove: PA = PB
Proof: In triangles OAP and OBP:
• OA = OB (radii of the same circle)
• OP = OP (common side)
• angle OAP = angle OBP = 90 degrees (radius perpendicular to tangent)
By RHS congruence: Triangle OAP is congruent to Triangle OBP
Result |
PA = PB (Corresponding parts of congruent triangles) |
3.3 Tangent Length Formula
From the right triangle formed by the external point P, the centre O, and the point of tangency A:
Tangent Length |
PA = sqrt(OP^2 - OA^2) = sqrt(d^2 - r^2) |
where d = distance from external point to centre, r = radius of the circle.
3.4 Angle Between Two Tangents
When two tangents PA and PB are drawn from external point P, and angle AOB is the angle at the centre:
Angle Between Tangents |
angle APB + angle AOB = 180 degrees |
This arises because OAPB is a cyclic quadrilateral and opposite angles in a cyclic quadrilateral sum to 180 degrees.
4. Solved Examples
Example 1: Finding Tangent Length
Problem: A point P is 13 cm from the centre of a circle of radius 5 cm. Find the length of the tangent from P to the circle.
Solution: Given: OP = 13 cm (distance from external point to centre) OA = 5 cm (radius) angle OAP = 90 degrees (radius perpendicular to tangent)
Using Pythagoras Theorem in triangle OAP: PA^2 = OP^2 - OA^2 PA^2 = 13^2 - 5^2 = 169 - 25 = 144 PA = 12 cm
Answer: Length of tangent = 12 cm |
Example 2: Angle Between Tangents
Problem: Two tangents PA and PB are drawn from an external point P to a circle with centre O. If angle APB = 70 degrees, find angle AOB.
Solution: We know that angle APB + angle AOB = 180 degrees
Therefore: angle AOB = 180 - 70 = 110 degrees
Answer: angle AOB = 110 degrees |
Example 3: Perimeter Using Equal Tangents
Problem: A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are 8 cm and 6 cm respectively. Find the sides AB and AC, if the perimeter of triangle ABC is 60 cm.
Solution: Let the circle touch AB at E and AC at F. Using equal tangent property: BD = BE = 8 cm (tangents from B) CD = CF = 6 cm (tangents from C) Let AE = AF = x (tangents from A)
Perimeter = AB + BC + CA = (AE + EB) + (BD + DC) + (CF + FA) = (x + 8) + (8 + 6) + (6 + x) = 2x + 28 = 60 2x = 32 => x = 16 cm
AB = AE + EB = 16 + 8 = 24 cm AC = AF + FC = 16 + 6 = 22 cm |
Example 4: Proving a Tangent
Problem: Prove that the tangents drawn at the ends of a diameter of a circle are parallel.
Solution: Let AB be a diameter of the circle with centre O. Let PQ be the tangent at A, and RS be the tangent at B.
Since OA is radius and PQ is tangent at A: angle OAP = 90 degrees (radius perpendicular to tangent)
Since OB is radius and RS is tangent at B: angle OBR = 90 degrees (radius perpendicular to tangent)
Now angle OAP = angle OBR = 90 degrees These are alternate interior angles for lines PQ and RS with transversal AB.
Therefore PQ is parallel to RS. [Proved] |
Example 5: Tangent to Incircle
Problem: A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB + CD = AD + BC.
Solution: Let the circle touch AB at P, BC at Q, CD at R, and AD at S.
By equal tangent lengths from each vertex: From A: AP = AS ...(1) From B: BP = BQ ...(2) From C: CQ = CR ...(3) From D: DR = DS ...(4)
Adding (1) + (2) + (3) + (4): AP + BP + CQ + DR = AS + BQ + CR + DS (AP + BP) + (CQ + DR) = (AS + DS) + (BQ + CR) AB + CD = AD + BC [Proved] |
5. Applications and Special Cases
5.1 Real-World Applications
• Road and Railway Design: Tangent lines are used in the design of smooth curves where a straight section meets a curved section of a road or rail track.
• Gear and Pulley Systems: The belt connecting two circular pulleys runs along the common external tangent, making tangent length calculations essential in mechanical engineering.
• Architecture and Art: Circular arches and domes use chord and tangent geometry. Stained glass designs and tiling patterns rely on circle-tangent relationships.
• Satellite Dish Alignment: The angle of a satellite dish is calculated using principles of tangent and secant lines from an external point.
• Navigation: Ship pilots use the concept of tangent lines when calculating the closest point of approach to a circular obstacle such as a reef or island.
5.2 Special Case: Right-Angle Triangle from External Tangent
When a tangent is drawn from an external point P to a circle with centre O and point of contact A, the triangle OAP is always a right-angled triangle with the right angle at A. This means:
• OP (hypotenuse) = sqrt(OA^2 + PA^2)
• The angle at P and the angle at O are complementary (sum to 90 degrees)
• The tangent length can always be found using Pythagoras Theorem
5.3 Special Case: Tangent-Chord Angle
The angle between a tangent drawn at a point on a circle and a chord drawn from the same point equals the inscribed angle subtended by the chord on the opposite side. This is called the Tangent-Chord Angle or the Alternate Segment Theorem and is used in higher geometry problems.
Alternate Segment Theorem |
Angle between tangent and chord = Inscribed angle in the alternate segment |
6. Formula Summary Table
All key formulas and results from this chapter are summarised below:
Concept | Formula / Result | Condition |
Tangent length from external point | PA = sqrt(OP^2 - r^2) | P is external, r is radius |
Radius-tangent angle | angle OAP = 90 degrees | A is point of contact |
Equal tangents | PA = PB | P is external, A and B are contacts |
Angle sum (two tangents) | angle APB + angle AOB = 180 deg | OAPB is a quadrilateral |
Tangent-Chord angle | angle = inscribed angle (alt. segment) | Alternate Segment Theorem |
Diameter | d = 2r | Basic relation |
Pythagoras in tangent triangle | OP^2 = OA^2 + PA^2 | Right angle at A |
Circumscribed quadrilateral | AB + CD = BC + AD | Circle touches all four sides |
7. Key Theorems and Properties
7.1 Summary of NCERT Theorems
Theorem | Statement | Proof Method |
Theorem 10.1 | The tangent at any point of a circle is perpendicular to the radius through the point of contact | Proof by contradiction using shortest distance |
Theorem 10.2 | The lengths of tangents drawn from an external point to a circle are equal | RHS congruence of triangles OAP and OBP |
7.2 Important Corollaries
1. The centre lies on the perpendicular bisector of the line segment joining the two points of contact from an external point.
2. The line joining the external point to the centre bisects the angle between the two tangents.
3. The line joining the external point to the centre also bisects the angle subtended by the chord of contact at the centre.
7.3 Properties of Tangent Lines
• A tangent meets the circle at only one point and does not cross it.
• Two circles can have 0, 1, 2, 3, or 4 common tangents depending on their relative positions.
• Two circles that are externally tangent (touch externally) have 3 common tangents.
• Two circles that are internally tangent (one inside the other, touching at one point) have 1 common tangent.
• Two circles that do not intersect and one is outside the other have 4 common tangents.
7.4 Common Tangents to Two Circles
Relative Position of Circles | Number of Common Tangents |
One circle inside the other (no contact) | 0 |
Internal tangency (touch internally) | 1 |
Intersecting at two points | 2 |
External tangency (touch externally) | 3 |
External (no contact, d > r1 + r2) | 4 |
8. Common Mistakes and Exam Tips
8.1 Common Mistakes to Avoid
Forgetting the perpendicularity condition: Students often fail to mark angle OAP = 90 degrees in diagrams. Always establish this before applying Pythagoras Theorem.
Confusing equal tangent lengths with equal angles: PA = PB does not mean angle OPA = angle POA. Use congruent triangles properly.
Missing the RHS step in theorem proof: In the proof of Theorem 10.2, the reason for RHS must be stated as radius perpendicular to tangent, not just right angle.
Not using the quadrilateral angle sum: When asked for angle APB, students sometimes try to calculate directly instead of using angle APB + angle AOB = 180 degrees.
Wrong variable assignment in perimeter problems: In circumscribed triangle/quadrilateral problems, assign tangent lengths from each vertex carefully using the equal tangent property.
8.2 Exam Tips for Full Marks
• Always draw a neat, labeled diagram for every question. Mark the right angle at the point of contact, label the centre O, and show radii and tangent lines clearly.
• In theorem proofs, write the statement, given, to prove, construction (if any), and proof separately. Each carries individual marks.
• For tangent length problems, immediately set up a right triangle and apply Pythagoras. The formula PA = sqrt(OP^2 - r^2) should become instinctive.
• In circumscribed polygon questions, always use the equal tangent property from each vertex to assign variables, then form an equation using the perimeter.
